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posted by  jdsmit10 on 9/4/2008 9:52:09 AM  |  status: Live  

Electrical Field 2

Course Textbook Chapter Problem
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Question Details:
 A solid sphere 1.7 cm in radius carries a uniform volume charge density. The electric field 0.85 cm from the sphere's center has a magnitude of 40 kN/C.
(a) At what other distance does the field have this magnitude?
 cm

(b) What is the net charge on the sphere?
 nC


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posted by Antony08 on 9/4/2008 10:12:14 AM  |  status: Live
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jdsmit10's comment:
"THanks"
Response Details:
(a)The electric field at a point inside the charged sphere is
E = (1/4πεo) * (qr/R3)
or q = [(E * R3)/(k * r)]
Here,E = 40 kN/C = 40 * 103 N/C,R = 1.7 cm = 1.7 * 10-2 m,k = 9 * 109 Nm2/C2 and r = 0.85 cm = 0.85 * 10-2 m
or q = [(40 * 103 * (1.7 * 10-2)3/(9 * 109) * (0.85 * 10-2)]
or q = 2.57 * 10-9 = 2.57 nC
 
The electric field at a point outside the charged sphere is
E = (1/4πεo) * (q/r2)
or r2 = (kq/E)
or r = (kq/E)1/2
or r = [(9 * 109) * (2.57 * 10-9)/(40 * 103)]1/2
or r = 2.4 * 10-2 m = 2.4 cm
 
(b)The net charge on the sphere is 2.57 nC.
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