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posted by  strawberrys on 7/25/2008 12:05:57 AM  |  status: Live  

Radioactive Decay

Course Textbook Chapter Problem
General Physics Physics: Principles with Applications (6th) by Giancoli N/A N/A
Question Details:
When Neon A=238, Z= 10 (mass = 22.9945 u) decays to Na A= 23, Z=11 (mass=22.9898 u), what is the maximum kinetic energy of the emitted electron? What is the minimum energy? What is the energy of the neutrino in each case? Ignore recoil of the daughter nucleus.

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posted by John(Cramster SME) on 7/25/2008 2:21:55 AM  |  status: Live
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Response Details:
 
   in each case if no electron is emitted the kinetic energy of the electron will be maximum
   if we negle ct the recoil of the sodium then the maximum kinetic energy of the electron will be
   KE = [m(23Ne) - m (23Na)] c2
         = [(22.9945 u) - (22.989767 u)] c2 (931.5 MeV / u c2)
         = ........MeV
   the minimum kinetic energy of the electron is zero
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