Given that the lenght of the rod is L = 0.47 m
the resistanc of the circuit is R = 13.7 Ω
magnetic field strength is B = 0.750 T
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Due to induced current in the circuit the force is F = BIL (along V vector )
= (0.750 T)(0.125A)(0.47m)
= --------- N
the rate of energy dessipated in the resister is H/t = I2R
= (0.125A)2(13.7Ω)
= --------- Joule/sec (or)W
if the rod is moving in the magnetic field then the induced emf is
ε = IR = BLv
v = IR /BL
power delecered to the rod is P = F*V
= F*I*R /BL
= ------ W