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posted by  GunnerAK on 7/24/2008 8:01:17 PM  |  status: Live  

light refraction

Course Textbook Chapter Problem
N/A N/A 25 N/A
Question Details:
A light ray initially in water enters a transparent substance at an angle of incidence of 35.0°, and the transmitted ray is refracted at an angle of 19.0°. Calculate the speed of light in the transparent substance.
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Oracle
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posted by link1320 on 7/24/2008 9:38:02 PM  |  status: Live
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Response Details:
Refraction index water, n1=1,33
Incident angle = 35º
Refracted angle = 19º

Snell's law:

n1 / sin (θ1) = n2 / sin(θ2)

We want to find n2 (refraction index of substance):

n2=n1*sin(θ2) / sin (θ1) = 1.33 * sin ( 19) / sin(35) = 0.7549

Speed of light in substance:

n = v/c , c= 3*10^8 m/s

v=n*c=0.7549*3*10^8 m/s = 2,26*10^8 m/s
Hope this helps. Don't forget to rate the answer.
Oracle
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posted by Kayen on 8/1/2008 10:22:18 PM  |  status: Live
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Response Details:
  n1  sin  θ1 = n2  sin θ2
With n1 = 1.333
       n2 = 1.33x0.5736/0.3256 = 2.35
Velocity, v = c/n = 3.0x108 / 2.35
                 = 1.28x108 m/s
 
Kayen (Enjoys helping you uderstand..)
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