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Temp, physics

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Scholar
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Date Posted: 7/24/2008 5:36:38 PM  Status: Closed
Temp, physics
Course Textbook Chapter Problem
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Question Details:
What mass of steam at a temperature of 100.0°C, must be added to 1.2 kg of ice at a temperature of 0.0°C to yield liquid water having a temperature of 35.0°C?
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Oracle
Karma Points: 8,290
Date Posted: 7/24/2008 5:51:00 PM  Status: Live
Asker's Rating: Lifesaver   
Response:
 
   By principle of caloriemetry
 
   Heat lost by steam   =   heat gained by ice
 
   ms * Lb +  ms * c * Δt1   =   mi * Lf +  mi * c * Δt2
 
   ms * {2256 + 4.2 * (100 - 0)}   =   1200 * { 334 + 4.2 * ( 35 - 0)}
 
   ms   =   5.772 * 105 / 2676   =   2.157 * 102   g   =   215.7   g   =   0.2157  kg



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