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Solving Equations (1) and (2) in step three

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Question:

Cramster Expert

(Cramster SME)

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Cramster In-House Subject Matter Expert

Date Posted: 7/25/2008 1:09:25 AM Status: Live

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Response:

for the given problem let I₁ be the current in the first branch through 0.01 Ω from bottom to the

top, I₂ be the current in the second branch through 1.00 Ω from top to the bottom to the top and

I₃ be the current in the thuird branch through 0.06 Ω from top to the bottom

applying the kirchoffa voltage law to the outer part we get

+ 12 V - (0.01 Ω) I₁ - (0.06 Ω) I₃ = 0

applying the kirchoffs voltage law to the right most loop we get

+ 10 V + (1.00 Ω) I₂ - (0.06 Ω) I₃ = 0

the relation between the three currents is

I₁ = I₂ + I₃

so solve for the currents I₂ and I₃ in the starter and in the dead battery

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