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posted by  Peas on 7/24/2008 1:32:05 PM  |  status: Live  

Kirchhoff's Rule

Course Textbook Chapter Problem
Algebra Based Physics College Physics (7th) by Serway, Faughn, Bennett N/A N/A
Question Details:
Using Kirchhoff's rules (and given emf1 = 70.3 V, emf2 = 60.0 V, emf3 = 78.7 V) calculate the following.


Figure P18.23

(a) Find the current in each resistor shown in Figure P18.23.
IR1 = wrong check mark
Your answer differs from the correct answer by 10% to 100%. mA
IR2 = mA
IR3 = mA
(b) Find the potential difference between points c and f.
emfcf = V

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posted by John(Cramster SME) on 7/25/2008 12:55:22 AM  |  status: Live
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Response Details:

(a)
   from the given circuit let us assume that the current in both of the loops is in clockwise
   direction
   the current in the left loop is i1 and in the right loop is i2
   then using the kirchoffs mesh analysis we get
   70.3 – 60.0 - (3.0 x 103) (i1 - i2)  - (2.0 x 103) i1 = 0 and
   60.0 - (4.0 x 103) (i2) – 78.7 - (i2 - i1) (3.0 x 103) = 0
   solve the above two equations for i1 and i2
    the current in the 2 kΩ resistor will be
   I2 kΩ = i1
            = ......... amps
   I4 kΩ = i2
            = ......... amps
   I3 kΩ = i1- i2
                = ......... amps
(b)
    the required potential difference will be
   V = (60.0 V) + [(I3 kΩ) (R2)]
       = ......... V
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