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Question:

A 45 m length of wire is stretched horizontally between two vertical posts. The wire carries a current of 68 A and experiences a magnetic force of 0.15 N. Find the magnitude of the earth's magnetic field at the location of the wire, assuming the field makes an angle of 50.5° with respect to the wire.

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Answers:

sapporo

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Karma Points: 2,790

Date Posted: 7/24/2008 1:06:00 PM Status: Live

Asker's Rating: Lifesaver

Response:

♦ F=I*[L × H], where I = 65A, |F| = 0.15N, |L|=45m, |H| is magnetic field to be found;
♥ |F| = I* |[L × H]| = I* |L| *|H| *sin(50.5°);
hence |H| = |F| /{I*|L|*sin(50.5°)} =0.665·10(-6) Tl;
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KimS's Comment:

thanks for your timely response and explanation !

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Physics Magnetic field. Help is appreciated; will rate !

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