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Date Posted: 7/24/2008 12:05:53 PM  Status: Live
physics3
Course Textbook Chapter Problem
N/A N/A N/A N/A
Question Details:
a mass of 0.40kg, hanging from a spring with a spring constant of 80N/m, is set into an up and down simple harmonic motion. what is the speed of the mass when moving through the equilibrium point? the starting displacement from equilibrium is 0.10m.
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Karma Points: 895
(Kansas State University)
Date Posted: 7/24/2008 12:16:23 PM  Status: Live
Asker's Rating: Lifesaver   
Response:
Set up an equation for the conservation of energy.
Kinetic Energy = Potential Energy
E=KE+PE
KE= (1/2)mv2      =0 when the spring is completely stretched
PE = (1/2)kx2 for a spring =0 when the spring is at the equilibrium point
therefore, the energy when KE is maxed is equal to the energy when PE is maxed.
KE=PE

(1/2)kx2 = (1/2)mv2

Just plug in values and solve for v
0.5*80*0.12=0.5*0.4*v2

v=1.41 m/s
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