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Scholar
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Respect (94%):
Date Posted: 7/24/2008 11:44:17 AM  Status: Closed
Magnitude electrostatic force
Course Textbook Chapter Problem
Calculus Based Physics Fundamentals of Physics Extended (8th) by Resnick, Halliday, Walker N/A N/A
Question Details:
If Q = 30 μC, q = 5.0 μC, and d = 30 cm, what is the magnitude of the electrostatic force on q in N? (ke = 8.99 x 10 9 Nm2/C2)


Important: Please include the formula.

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Date Posted: 7/24/2008 1:53:29 PM  Status: Live
Asker's Rating: Lifesaver   
Response:
The "formula"? What formula?
 
If you mean the equation, then its
 
  Force  =   k  q1 q2 / r2            where r is the distance between the charges.
 
That should be in your book... you shouldnt have to wait for someone to give it to you here.
 
Anyway... this problem is not complicated.
 
force between Q and q:
 
         F  = k Q q / d2  =
 
               =  8.99 x 109 * 30 x 10-6 * 5.0 x 10-6 / 0.302  =
 
                 =    14.983 Newtons     to the right (because its repulsive)
 
force between 2Q and q:
 
         F  = k 2Q q / (2d)2  =
 
               =  8.99 x 109 * 60 x 10-6 * 5.0 x 10-6 / 0.602  =
 
                 =    7.492 Newtons     to the left (because its repulsive)
 
total force on q  =  14.983  -  7.492    =  7.491 Newtons,  to the right
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