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Physics: Coefficient of Kinetic Friction

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Question:

A potter's wheel having a radius 0.53 m and a moment of inertia 15 kg·m² is rotating freely at 45 rev/min. The potter can stop the wheel in 7.5 s by pressing a wet rag against the rim and exerting a radially inward force of 75 N. Find the effective coefficient of kinetic friction between the wheel and the wet rag.

Answers:

Cramster Expert

dhara

(Cramster SME)

Cramster In-House Subject Matter Expert

Date Posted: 7/24/2008 7:31:03 AM Status: Live

Asker's Rating: This answer has not been rated. If you asked this question, then please login.

Response:

The moment of inertia is

mr² = 15

Here, r = 0.53m.

Therefore,we get

m = (15/(0.53)²) = 53.4kg

The rotational force on the wheel is

F = mα = m * (w/t) = 53.4 * (0.75/7.5) = 5.34N

Therefore,the coefficient of kinetic friction is

μ_k = (5.34/75) = 0.07.

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Physics: Coefficient of Kinetic Friction

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