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posted by  monna on 7/24/2008 12:25:00 AM  |  status: Live  

I need Help...will rate life saver

Course Textbook Chapter Problem
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Question Details:
An individual is nearsighted; his near point is 16.0 cm and his far point is 59.0 cm.
(a) What lens power is needed to correct his nearsightedness?
diopters
(b) When the lenses are in use, what is this person's near point?
cm
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posted by link1320 on 7/24/2008 1:03:28 AM  |  status: Live
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Response Details:
The object distance
Far point of eye

a)

Then


 

So power

              

            

b)

Near point of an eye q= -16cm

When lenses are in used then







   

   

The person near point will be



Hope this helps. Don't forget to rate the answer.
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posted by monna on 7/24/2008 1:09:54 AM  |  status: Live
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Response Details:
B appears to be wrong...I looked at your answer again, but your math seems right...I do not know where is the problem?
Oracle
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posted by link1320 on 7/25/2008 12:12:27 AM  |  status: Live
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Response Details:
I think that's fine, maybe the website requires that you put more decimal places, try putting this: 23.809 cm or 24 cm.
Hope this helps. Don't forget to rate the answer.
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posted by monna on 7/26/2008 4:25:43 AM  |  status: Live
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Response Details:
I got the right one it is 21.95
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