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Please help (Thermodynamics)

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Apprentice
Karma Points: 107
Respect (99%):
Date Posted: 6/29/2008 9:23:39 PM  Status: Live
Please help (Thermodynamics)
Course Textbook Chapter Problem
N/A N/A N/A N/A
Question Details:
An unknown object of mass ms, is added to water of mass mw. The initial temperature of the unknown object is Ta and the initial temperature of the water is Tb. The system comes out to equilibrum with temperature Tf. Derive an experssion for the speicfic heat of the unknown object. Ignore the heat lost to the container, there are no phase changes during this process.

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Mentor
Karma Points: 657
Date Posted: 6/29/2008 10:10:10 PM  Status: Live
Asker's Rating: Lifesaver   
Response:

HEat gained/lost by Object S = Heat gained/lost by Water        ( because you didn't specify which one gained/lost heat)
Heat  = mcΔt

mscs(Tf - Ta)  = mwcw(Tf - Tb)          where cs is the specific heat of the unknown object
                                                               
c= mwcw(Tf - Tb)/ms(Tf - Ta

OR 
Because we know heat capacity of water cw to be 4.184 J/gC, we can substitute this so
c= 4.184mw(Tf - Tb)/ms(Tf - Ta

That's the answer. Please dont forget to rate me. Feel free to ask additional questions.


miss.bossyy's Comment:
thank u


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Oracle
Karma Points: 21,845
(Ohio University Main Campus)
Date Posted: 6/29/2008 10:13:14 PM  Status: Live
Asker's Rating: Helpful   
Response:
Calorimetry problems are a bit tricky esp in using different units. But here there are no units involved; it is easy. If you have other qns send me a message.
Heat transferred is always either,
          Q = m.c.ΔT due to change in temp ΔT; or
          Q' = m.L due to phase change.
We assume the unknown object temp Ta > temp of water, Tb
Heat lost by the unknown object,
         Q = mc.ΔT = ms.cs.(Ta - Tf
Heat gained buy water,
         Q2 = mc.ΔT = mw.cw.(Tf- Tb
Since there is no other loss or gain, these4s two must be equal
(Principle of calorimetry).
       ms.cs.(Ta - Tf) = mw.cw.(Tf- Tb
Sp heat capacity of the unknown object,
            cs = mw.cw.(Tf- Tb)/[ms(Ta - Tf)]
Here    cw is sp heat of water = 1 cal/goC or 4.186 J/goC.
 
 
 
 
miss.bossyy's Comment:
I wish I could give u more points...but I really appericate your help:-)...thanks u so much...u r genius

 
Kayen (Enjoys helping you uderstand..)
Please do not forget to Rate my Response.



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