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Getting the volume of water escaping per minute

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Date Posted: 6/18/2008 5:58:40 AM  Status: Closed
Getting the volume of water escaping per minute
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Question Details:
Question:
   What volume of water will escape per minute from an open-top tank through an opening 3 cm in diameter that is 5m below the water level in the tank?


Hmm... So the answer should be in (m^3)/min right? if that's the case, how will I relate the time??

Answers:

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Date Posted: 6/18/2008 6:18:10 AM  Status: Live
Asker's Rating: Lifesaver   
Response:
speed of water escaping  =  √2gh  =  √2*9.8*5  =    9.90 m/s
 
flow rate is  speed times area or
 
   flow rate  = 9.90 m/s  *  π * (0.015 m)2  =   0.006998 m3 / second
 
or    0.006998 * 60  =      0.420  m3 / minute
 
the time is related because    speed x area  is equal to  volume per time
jehuty23's Comment:
thank you very much... now i get it!
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Date Posted: 6/18/2008 6:19:43 AM  Status: Live
Asker's Rating: Helpful   
Response:
v=√2gy

=√2(9,8*5)

=9.899494937m3ls * 60secs/1min

=593.97m3/min

A= πr2

=π(.0152)

=0.000706858

Q=Av

=0.00706858(593.97)

=0.419852652m3/min

Tol kay prof darwin saludez ka db? may sagot ka na sa number 4 question? ung hydrostatics
jehuty23's Comment:
sayang ndi na kta pdeng mbgyan ng life saver... hehe ty pa rin



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