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posted by  Ali G on 5/27/2008 10:58:36 PM  |  status: Closed  

e/m of the electron

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Question Details:
The trajectory of charged particle is (1)          in a constant magnetic field and (2)          in a constant electric field.

A) (1) parabolic, (2) parabolic
B) (1) linear, (2) parabolic
C) (1) circular, (2) parobolic
D) (1) parabolic, (2) linear
E) None of the above
I thought that the trajectory was (1) circular and therefore (2) would be parabolic but I'm not sure nor am I sure I understand it.  
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posted by Suebee on 5/28/2008 12:02:33 AM  |  status: Live
Asker's Rating: Lifesaver   
Ali G's comment:
"thanks for your help"
Response Details:
The magnetic force acting on a chared particle moving in a magnetic field is always perpendicular to the velocityof the particle.  So the charged particle moves in a circle whose plane is perpendicular to the magnetic field.
 
For the electric field; a charged particle between the plates:   x = vo t , solve for t and plug into y = 1/2 a t2.  We see that y is proportional to x2.    Henc, the trjectory is a  parabola.
 
                     y = 1/2 a ( x/vo )2  = 1/2 a (x2 / vo 2 )
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