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Motion on an Inclined Plane

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Date Posted: 5/10/2008 11:05:32 PM  Status: Live
Motion on an Inclined Plane
Course Textbook Chapter Problem
Algebra Based Physics College Physics (8th) by Young 2 N/A
Question Details:
A bowling ball rolls along a level surface, then up a 30 degree slope, and finally exits onto another level surface at a much lower speed.
 
a. Draw a position, velocity, and acceleration-versus-time graphs for the ball
 
 
 
 
 
I think I did this right.  But I just wanted to make sure.  I made a diagram of the different graphs to make it easier to answer this question.  Thanks!!
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Mentor
Karma Points: 738
Date Posted: 5/10/2008 11:57:26 PM  Status: Live
Asker's Rating: Helpful   
Response:
I'm assuming you just want a sketch of the graphs' shape so...
1. Rising slope, then slowing curve, and then a less steep rising slope.
-Rising slope is because of the initial velocity, which is unchanging before the ball hits the slope, thus the displacement increases steadily.
-Curve is for the slope; due to acceleration of gravity (downwards, opposite to the vertical component of the velocity on the slope) , so the displacement grows less and less per unit of time.
-Velocity is constant again after the slope, so the displacement grows steadily again. It grows at a lesser rate, since the velocity is lower. 
 
2.Horizontal line, then falling slope, then horizontal line again.
-Horizontal line because the initial velocity experiences no acceleration.
-Falling slope is during the ramp where gravity lowers the velocty.
-Horizontal line again because the velocity is constant again, but is lower than the initial so the "Vx" value is less.
3. Horizontal line
-The acceleration to gravity occurs at all times, so the acceleration is a constant horizontal line. It only acts opposite to the velocity when the ball goes up the ramp, so thats the only time when the velocity decreases.

Physics doesn't suck; it just blows.

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Date Posted: 5/11/2008 12:28:00 AM  Status: Live
Asker's Rating: Lifesaver   
Response:
 
This is the displacement vs time graph.  The displacement on the graph where the ball hits the hill curves downward, because it is a negative acceleration.  It is constant before and after the hill.
 
 
Here is the velocity versus time graph, where velocity is constant before the hill, a negative slope on the hill, and constant after the hill.
 
 
Here is the acceleration versus time graph.  The acceleration starts at 0, then drops down to a constant negative value, then goes back to zero after the hill.  *Note* This is assuming that you want the horizontal acceleration, I am neglecting the vertical acceleration to gravity, which (ignoring friction) does not affect the ball's velocity until it hits the hill, which is where you see the low point on the graph.
Red_42's Comment:
Thank you!!



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