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Deceleration

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Scholar
Karma Points: 200
Respect (94%):
Date Posted: 5/8/2008 8:53:53 PM  Status: Live
Deceleration
Course Textbook Chapter Problem
General Physics N/A N/A N/A
Question Details:
A person weighing 490 N stands on a scale in an elevator.  The elevator is moving upward with a deceleration of 2 m/s squared.  The reading on the scale is nearly equal to:
 
a)zero
b) 390 N
c) 490 N
d) 590 N
e) none of them
 

Answers:

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Scholar
Karma Points: 201
Date Posted: 5/8/2008 9:04:56 PM  Status: Live
Asker's Rating: Helpful   
Response:
Person weighs 490/9.80m/s2 = 50kg
 
acceleration is now 9.80m/s2 down - 2m/s2 up = 7.80m/s2
 
so person weighs 50kg * 7.80m/s2 = 390 N (B)
RN's Comment:
Thanks for the correction.. mega dido's!

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Expert
Karma Points: 1,024
Date Posted: 5/8/2008 9:05:45 PM  Status: Live
Asker's Rating: Not Helpful   
Response:

w2=w1(g+a)
     =490(9.8-2)
     =3822


RN's Comment:
Thanks for trying..more than I could get!



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Guru
Karma Points: 2,126
(Paideia (Atlanta, GA))
Date Posted: 7/1/2008 2:08:04 PM  Status: Live
Asker's Rating: Helpful   
Response:

b) 390 N

RN's Comment:
i rate higher for early responses thx

Rate or not rate!!! What goes around comes around!!!



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