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posted by  shorty09 on 4/22/2008 10:37:28 AM  |  status: Live  

Circuit Analysis

Course Textbook Chapter Problem
Algebra Based Physics N/A N/A N/A
Question Details:
 
Req=22kΩ. What is the current in R1?
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posted by Michaelh on 4/22/2008 10:51:44 AM  |  status: Live
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Response Details:

We know that 400μA flows through 30k         =>      V = IR = 12 V

 
Since 30k and 20k are in parallel, they have the same voltage. Therefore, the voltage across the middle resistor is 12V as well
 
Therefore, the current through R2 is I = V/R = 12/20k = 600μA
 
From KCL:
 
The current through R1 is 400 + 600 = 1mA
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