SORRY! I mis-read the beginning of the question. It's still attached to the spring. So, If it is still attached, it must be slowing down since the spring should now be pulling on it.
It asks you for its speed .25 m from its starting point. Well, we know how far the spring was compressed and therefore how far the glader has moved since that point.
So subtract the .18 m from the .25m and you should get .07m as a distance traveled since.
Now use the information from part A to detirmine the rate change of velocity due to the force of the spring.
If v = 1.1259778359053076 m/s at the end of the .18m then to find acceleration, we use:
now sub in your info:
2*.18 =
DIVIDE BY .36m
Now use this to do the rest of the problem:
If that was its acceleration when it was increasing its speed, then the negative of that would be its "decelleration" when the spring pulling on it is slowing it down.
Now use the same formula you did above:
your initial velocity is the final velocity in part A)
Take the square root:
This is your answer for part B)
Hope this helps a little more. Sorry about before. Please let me know if it works!