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Urgent Please help

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Question:

Answers:

Simmy

Scholar

Karma Points: 312

Moderator

(University of Southern California)

Date Posted: 7/18/2007 4:39:52 PM Status: Live

Asker's Rating: Lifesaver

Response:

f(x) =(x-3)^2 with

A) Graph f(x) does it pass vertical & horizontal tests?

the graph starts at (3,0) and is exponential. It passes both the vertical and horizontal line tests.

B) Find Inverse f ^-1 (x)

To find the inverse, you must swap x and y.

Your equation becomes x = (y-3)^2. Now you have to rearrange to once again solve for y.

√x = (y-3)

y = √x + 3 OR f(x) = √x + 3

C) Graph the inverse function f^-1 (x)

this graph starts at (0,3) - notice that is the same as the previous graph, just flipping the numbers around.

D) Domain of f(x)

Range of f(x)

, that means the quantity (x-3) will equal anything from 0 to ∞. Squaring the (x-3) won't change that -- the quantity

will still equal anything from 0 to infinity. Therefore, your range is

Your domain is given:

Domain f ^-1 (x)

Range f ^-1 (x)

the domain is

since you can't have the square root of a negative number, and the range is

Notice how the domain of your inverse is the range of your original function, and the range of your inverse is the domain of your original function.

With the extra help, if you could please edit your rating for me I'd appreciate it, thanks!

Morre's Comment:

Thank You- Seeing it makes it more comprehendable

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Urgent Please help

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