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Date Posted: 7/24/2008 4:32:10 AM  Status: Live
static R.C. Hibbeler
Course Textbook Chapter Problem
Classical Mechanics Engineering Mechanics - Statics 11th by Hibbeler 2 119
Question Details:
 
 
 
rA= {6i+7j-2k}       
  uA= F=80*uA 
       = {35.29i+9.24j-2.6k}

rAB={-6i-3j+2k}      
uAB= rAB/|rAB|  
        =   {-6i-3j+2k} /7
 
FAB  = F x rAB 
 
         =   -34.60 N

Answers:

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Karma Points: 348
Date Posted: 7/24/2008 11:34:09 AM  Status: Live
Asker's Rating: Helpful   
Response:
 
sorry for the bad diagram , but u can find the answer
 here   rA is the position vector from  A to H
 so rA =CH - CA
where CH= 0i+0j-12k
 and    CA=6i+7j-2k
 
so    rA   =  (0i+0j-12k) - (6i+7j-2k)
 
       rA   = -6i -7j-(12+2)k
              = -6i -7j -10k.
 

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Date Posted: 7/24/2008 7:52:06 PM  Status: Live
Asker's Rating: N/A-Posted by Person Asking Question   
Response:
Thanks



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