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posted by  staticskid2 on 7/19/2008 12:52:28 PM  |  status: Closed  

Moment of Inertia, Ix, Iy - Will rate LIFESAVER!!!! Please Help!!

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Classical Mechanics Vector Mechanics for Engineers: Statics (8th) by Johnston, Eisenberg, Beer N/A N/A
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posted by rooya on 7/22/2008 12:03:32 PM  |  status: Live
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staticskid2's comment:
"Thank you soo much!!"
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consider the forur rectangles
 
FOR X AXIS
      (Ix)1=1*9^3/4 =182.25
       (Ix)2=10*1^3/12 +  (1*10)(9+0.5)=903.33
      (Ix)3=3.5*0.5^3/12 + (3.5*0.5)(9-0.25)^2 =134
      (Ix)4=0.5*3^3/12 +(3*0.5)(9-0.5-1.5)^2=74.625
    (Ix) = (Ix)1+ (Ix)2+ (Ix)3+ (Ix)4
     (Ix)=182.25+903.33+(2*134)+(2*74.625)
       (Ix)=1502.83
FOR Y AXIS
 
     (IY)1=9*1^3/4 =0.75
       (Ix)2=1*10^3/12 =83.33
      (Ix)3=0.5*3.5^3/12 + (3.5*0.5)(3.5/2+0.5)^2 =10.646
      (Ix)4=3*0.5^3/12 +(3*0.5)(0.25+0.5)^2=0.874
   (Iy) = (Iy)1+ (Iy)2+ (Iy)3+ (Iy)4
     (Ix)=0.75+83.33+(2*10.646)+(2*0.874)
       (Ix)=107.12
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