Given
aA=0.75
VB=6
but it is given that bus reaches point O in 20sec
Distance travelled by bus B in 20s
D=VB*t=6*20=120
Let t be the time taken when A&B meet
Distance travelled by A
we know that
S=Ut+at^2/2
x=0+1/2*0.75*t^2
x=0.375t^2 ------------(1)
but Distance travelled by B
(120-x)=VB*t------------------(2)
x=120-6t
from 1&2
120-6t=0.375t^2
t=11.6 s
from 1
x=50.46 m