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posted by  ale_g_20 on 7/14/2008 4:50:46 PM  |  status: Live  

urgent11.41

Course Textbook Chapter Problem
Classical Mechanics Vector Mechanics for Engineers: Dynamics (8th) by Johnston, Beer, Clausen 11 N/A
Question Details:
Can you solve this problem please. I dont understand it! problem # 11.41
automobile A starts from O and accelerates at the constant rate of 0.75 m/s2.  A short time later it is passed by bus B which is traveling in the opposite direction at a constant speed of 6 m/s. Knowing that bus B passes point O 20 seconds after automobile A started from there, determine when and where the vehicles passed each other.
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posted by rooya on 7/19/2008 12:16:45 PM  |  status: Live
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Response Details:
Given
aA=0.75
VB=6
but it is given that bus reaches point O in 20sec
Distance travelled by bus B in 20s
D=VB*t=6*20=120
 
Let t be the time taken when A&B meet
Distance travelled by A
we know that
S=Ut+at^2/2
x=0+1/2*0.75*t^2
x=0.375t^2 ------------(1)
but Distance travelled by B
(120-x)=VB*t------------------(2)
x=120-6t
from 1&2
120-6t=0.375t^2
t=11.6 s
from 1
x=50.46 m
 
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