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Question:

A magnetic pickup is used to detect the shaft speed of a turbocharger. A standard hexagonal nut is used to excite the pickup. If the shaft is turning at 50,000 rpm, how many positive pulses will be created per second? By what number should the number of counts in a second be multiplied by to produce a result in rpm?

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Answers:

Cramster Expert

samuel(SME- Mech)

(Cramster SME)

Moderator

Cramster In-House Subject Matter Expert

Date Posted: 5/16/2008 9:22:22 AM Status: Live

Asker's Rating: Lifesaver

Response:

a hexagonal nut contains 6 faces

ie, for every revolution it gives 6 pulses

shaft revolutions/minute = 50,000

shaft revolutions/second = 50,000/60=833.33 REV/S

pulses created/sec = 833.33*6 =5000

let "x" be the counts that is multiplyed

5000*x=50,000

x=10

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