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posted by  PE on 7/23/2008 3:57:33 AM  |  status: Live  

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An induction motor has an efficiency of  0.80 when the load is 50 h.p. At this load , both stator copper loss and rotor copper loss are equal to the core losses . The mechanical losses are one -fourth of the no load losses . Calculate the slip. 

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posted by boon(EE-SME) on 7/23/2008 6:49:43 AM  |  status: Live
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"thanks"
Response Details:
Given,
Efficcency,
Motor output,
We know,
Motor input
Therefore total losses,
These losses include
(i) Stator copper and core losses
(ii) Rotor copper losses
(iii) Rotor mechanical losses
Now no-load losses of an induction motor consists of
(i) Stator core losses, and
(ii) Mechanical losses,
i.e.,
Therefore

 
Let,
Stator core loss,
then Stator copper loss,
also Rotor copper loss,
Mechanical losses,
Therefore
Now, rotor input = motor ouput + mechanical losses + rotor copper losses
 
Hope this helps you...
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