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Magnetic circuits

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Scholar
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Date Posted: 7/21/2008 10:46:41 AM  Status: Closed
Magnetic circuits
Course Textbook Chapter Problem
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Oracle
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Date Posted: 7/21/2008 2:09:03 PM  Status: Live
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Response:
I) Using the right hand rule,  the magnetic fluxs for the given current direction aids, hence mutual voltage and self induced voltages are of same polarity
II) Using the right hand rule,  the magnetic fluxs for the given current direction are opposite, mutual voltage and self induced voltages are of opposite polarity.
 
III ) L = 2H, L2 = 8H, M=3H
M = K √L1L2
K = M / √L1L2
K= 3/ √(2)(8) = 3/ √16 = 3/4 = 0.75
 
b)
In the given circuit the current enters the first & second coil by the dot terminals, hene the sigm of M terms and L terms will be the same
M = K √L1L2
M = (0.5) √ (4) (16) = 0.5 ( √64) = (0.5) (8) = 4H
Applying KVL to the loop 1
Applying KVL to the loop 2
 



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