Given
L = 10mH, R = 20Ω, fr = 15kHz, V=120V
The resonant frequecny is given by
fr = 1/ 2π√LC
squring and rearranging
C = 1/ 2π2fr2L
C= 1/ (2)(3.14)2 (15000)2 (0.01)
C = 2.25*10-8 F
or
C = 22.5nF
b) At resonance the impedance of the circuit is
Z =R
the current is given by
I = V/R = 120 / 20 =
6A
c) The Q factor is given by
Q = [1/R] [√L/C]
Q = [1/20] [√( 0.01/ 22.5n)] = 33