Cramster.com - Homework Solutions, Lecture Notes, Exams, and Free Online Homework Help
Sign Up Now! Login Customer Support Cramster Blog
McAfee Secure sites help keep you safe from identity theft, credit card fraud, spyware, spam, viruses and online scams
Problem Solved.
    Home    
    Homework Help    
   Answer Board   
    Resources (Beta)    
   
You Are Here: Home > Answer Board > Electrical Engineering > Topic: Kirchoff's Rule - Lifesaver
Member's Topic Headline:

Kirchoff's Rule - Lifesaver

Know the answer? Have a better solution? Share it.
Get Help Now.
View homework problems
explained for free!
Member Testimonials

Question:

Advertisement:
Answer | Ask New Question | Customize Profile | Leaderboards | 
FAQ

Member's Avatar
Rookie
Karma Points: 0
Respect (88%):
Date Posted: 7/11/2008 11:27:38 PM  Status: Live
Kirchoff's Rule - Lifesaver
Course Textbook Chapter Problem
N/A N/A N/A N/A
Question Details:
Resolved by the Kirchoff's Rule

Answers:

Member's Avatar
Rookie
Karma Points: 5
Date Posted: 7/12/2008 5:36:20 AM  Status: Live
Asker's Rating: Helpful   
Response:
 lets start with the inner loop eq.:
4V=(1)ΩI1+(5)ΩI1+(8)Ω(I1+I2)
4=14I1+8I2
I1=4\14- (8/14)I2
the outer loop eq.:
12V=1Ω(I2)+3Ω(I2)+8Ω(I1+I2)
12=12I2+8I1
12=12I2+8{(4/14)-(8/14)I2}
after solving these equations we should be able to find the loop currents then it will be easy to find the voltages of each resistance
 



By reading or posting messages on these forums, you are agreeing to the Answer Board's Terms of Service and Conduct (TSC).


About Cramster | Terms of Use | Privacy Policy | Contact Us | Press Room | Site Map | Support | Anti-Cheating Policy

Cramster.com is not affiliated with any publisher. Book covers, title and author names appear for reference only.
Copyright © 2008 Cramster, Inc.