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posted by  DoRi on 7/10/2008 12:42:14 AM  |  status: Live  

Mistake!??!????

Course Textbook Chapter Problem
Analog Circuits Basic Engineering Circuit Analysis (8th) by Irwin 12 31P
Question Details:
general transfer function :

1/s : at 0db .... 1w
10/s : at 0db....10w

in the problem at 0db ....12w
so it should be 12/s

conclusion :
14.4 (s+8) (s+60)
_______________
s(s+1)(s+40)
what do you think?

AAnswers:

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posted by prince(EE-SME) on 7/10/2008 5:29:43 AM  |  status: Live
Asker's Rating: None Provided    Moderator's Rating: N/A
Response Details:
Iam solving total problem. u can check where u made a mistake.
what ever u told is correct. In the the next  steps u may did some mistake. Here is the complete solutions.


Since the initial slope is -20 db so it represents a single pole 's' and it crosses 0db at ω=12 rad/sec
so the transfer function is
 
 
and at next  slope is -40 db/decade and it starts from ω=1 rad/sec and there is a pole at ω=1rad/sec
∴Trasfer function for that line =
 
 
and next slope -20 db/decade and it starts from ω=8 rad/sec it indicates that there is zero at ω=8rad/sec
∴Transfer function for that line=
 
an next slope is 0 db/decade and it starts from ω=60 db/decade it indicates that there is zero at ω=60rad/sec
∴Transfer function for that line=
 
 
 
and next slope -20 db/decade and it starts from ω=400 rad/sec it indicates that there is zero at ω=400rad/sec
∴Transfer function for that line=
 
 
so overall Transfer function is
 
∴T/F =
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