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Current values - Lifesaver

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Answers:

prince_s

Expert

Karma Points: 1,208

Date Posted: 7/9/2008 1:36:54 AM Status: Live

Asker's Rating: Lifesaver

Response:

Equallant resistance of the circuit is

R₃ R₄are in parallel.

So equallant Resistance is

R₇R₈R₉ are in parallel

So equallant Resistance is

From this

R_2mn5=R₂+R_mn+R₅

R_2mn5=1k+0.875k+5k

R_2mn5=6.875kΩ

and

R_6wz10=R₆+R_wz+R₁₀

R_6wz10=4k+1k+8k

R_6wz10=13kΩ

from this

R_xy=4.49kΩ

Rab=4k+4.49k+5k

Rab=13.49kΩ

so from current in that circuit is

from this

and to find I₁

From current division rule

I₃=0.8488mA

I₄=0.1213mA

In the diagram there is I₂

I think I₂ is in flowing through the branch wz

so through that branch is

nux2009's Comment:

Thanks again!!!!!!!

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Current values - Lifesaver

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