Given that
The work function of Cr, W = 4.40 eV
= 4.4*1.6*10-19 J
The wave length of radiation λ = 200 nm
= 2.0 *10-7 m
We know that
(hc/λ) = W + K.E
∴ Kinetic energy K.E = (hc/λ)- W
= { (6.626*10-34 J s *3.0*108 m/s) / (2.0*10-7 m)}- 4.4*1.6*10-19 J
= 9.939*10-19 J - (4.4*1.6*10-19 J)
= 2.899*10-19 J
=
1.8118 eV
The kinetic energy of electrons emitted from a chromium surface = 1.8118 eV