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Scholar
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posted by  marvin on 7/24/2008 10:11:47 AM  |  status: Live  
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Preparing for my test

Course Textbook Chapter Problem
General Chemistry isbn 0-13140221-8 N/A N/A
Question Details:
  Hi every one I need some help working through these problems I have a test tomorrow,  And keep getting stuck
Thanks
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Sage
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posted by Jesley on 7/24/2008 10:48:10 PM  |  status: Live
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a)   [H3O+]= 3.4x10-9
pH = -log [H3O+]= -log(3.4x10-9 )
pH = 8.47>7.00 (Basic solution)
pOH +pH = 14
pOH = 14-pH = 14- 8.47= 5.53
pOH = -log[OH-]
[OH-] = 10-5.53 = 2.95x10-6M
 if pH <7 (acidic), pH=7(neutral)
can you please calculate for the others in the same way
Scholar
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posted by marvin on 8/6/2008 9:03:27 PM  |  status: Live
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Response Details:
grate thanks
sorry for the delayed responce busy studying
 
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