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posted by  PoorLamb on 7/22/2008 2:03:11 PM  |  status: Live  

Minimum concentration (WILL RATE LIFESAVER)

Course Textbook Chapter Problem
General Chemistry Chemistry: The Central Science (10th) by Brown, Lemay, Bursten 16&17 N/A
Question Details:
If a concentration of Ca2+ in a kidney is 0.0050M, at what minimum oxalate concentration do you expect CaC2O4 (Ksp=2.3*10-9) to be precipitated to form a kidney stone?

a) 2.2*106 M
b) 1.2*10-6 M
c) 2.2*10-6 M
d) 4.7*10-7 M
e) 1.2*10-11 M
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posted by Ricky Wilkins on 7/22/2008 9:18:13 PM  |  status: Live
Asker's Rating: Lifesaver   
Response Details:
 In aq.solutions CaC2O4  dissociates in to Ca+2 and C2O4-2 ,Thus
     CaC2O4 ----------->  Ca+2 (aq)  + C2O4-2(aq)
  
 Therefore Ksp = [Ca+2][ C2O4-2]
       2.3*10-9   = 0.0050M * s
              s        = 460 * 10-9 M
                  s     = 4.6 * 10-7 M(Oxalate concentration)
     
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