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Physical Chemistry Adiabatic

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Question:

Jesley

Sage

Karma Points: 4,268

Date Posted: 6/27/2008 12:25:47 AM Status: Live

Asker's Rating: Lifesaver

Response:

we know that,

C_p-C_v= R ==> C_P= R+C_v

since , C_v= 5/2 R

∴C_p= 7/2R

but the exponential constant, γ= (C_p/C_v) = (7/2)/(5/2) = 1.4

for an adiabatic process, we have the relation , PV^γ= constant

P₁V₁^γ=P₂V₂^γ

given , P₁= 1atm, V₁= 1025cm³, T₁= 25⁰C=25+273=298K, V₂= 25cm³

(P₂/P₁)= (V₁/V₂)^γ= (1atm)(1025/25)^1.4= 181atm

from , P₁V₁/T₁=P₂V₂/T₂

==> T₂/T₁= (V₁/V₂)^(γ-1)

==> T₂= T₁ (V₁/V₂)^(γ-1)

==>T₂= (298K)*(1025/25)^(1.4-1)= 1316K = 1043⁰C

Jack Alope's Comment:

thanks!

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