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posted by  Jack Alope on 6/26/2008 2:15:32 PM  |  status: Live  

** Physical Chemistry - Carnot **

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Physical Chemistry N/A N/A N/A
Question Details:
Show that Σ(q/T) = 0 ; derive the Carnot efficiency.
 
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posted by Jesley on 6/27/2008 4:11:21 AM  |  status: Live
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Response Details:
the efficiency of a heat engine is
η = net work output/heat absorbed = (QH-QC)/QH
it can also be expressed as, η = (TH-TC)/TH
combining these equations
1- (QC/QH)=1-(TC/TH)
(QC/TC)=(QH/TH)
(QH/TH)-(QC/TC)=0
If we take Q to represent heat  added to the system, then heat taken from the system will have a negative value. For the Carnot cycle
Σ(Q/T)=0

 
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