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posted by  PleaseHelp08 on 7/24/2008 5:04:19 PM  |  status: Live  

Definite Integrals

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Calculus N/A N/A N/A
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Evaluate the following
 

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posted by whitesirens on 7/24/2008 5:20:17 PM  |  status: Live
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Response Details:
Use integration by parts:

u = 2x+5 and dv = sin(6x-3)

thus, du = 2 dx   and    v = -(1/6)cos(6x-3)

the equation for integration by parts is uv - the integral of (v du)

so (2x+5)(-1/6)(cos(6x-3)) - the integral of (2)(sin(6x-3)

integrating 2sin(6x-3) becomes (-1/3)cos(6x-3)

and your final answer is ------ (2x+5)(-1/6)(cos(6x-3) + (1/3)cos(6x-3) + C

Hope that helps!!!
Tags: Math, Calculus
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posted by A-Rod 7821 on 7/24/2008 5:33:01 PM  |  status: Live
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Response Details:

 
Use Integration By Parts Formula:
 
u=(2x+5)
 
du=2dx
 
dv=sin(6x-3)dx
 
v=(-1/6)cos(6x-3)
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Tags: Math, Calculus
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