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posted by  T4RMINAT3R on 7/3/2008 1:13:27 AM  |  status: Live  

Setting up a Definitive Integral? Short question.

Course Textbook Chapter Problem
Calculus N/A N/A N/A
Question Details:
Set up a definite integral which is equal to the area bounded by the curves y = x³ + x² and y = 2x² + 2x.

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posted by Adielynnn on 7/3/2008 2:17:05 AM  |  status: Live
Asker's Rating: Somewhat Helpful   
Response Details:
Well to find a definite integral, first you must find where the two points where the graphs intersect, which will bound the area between them. Then those become your points a and b [hopefully you know what I mean by that: the integral from a to b, where a is on the bottom of the integral symbol and b is on the top]
Then on the right side of the integral will be (which ever curve is on top) - (which ever curve is on the bottom)dx
 
I hope that helps!
Tags: Math, Calculus
Oracle
Karma Points: 9,380
posted by Bpanda on 7/3/2008 2:17:14 AM  |  status: Live
Asker's Rating: Lifesaver   
T4RMINAT3R's comment:
"Thank you, your answer was very clear & also thanks for your time."
Response Details:
let's find where the two curves intersects each other:
 
f(x) = x3 + x2  = x2 ( x + 1)
g(x) = 2x2 + 2x  = 2x( x + 1)
 
f(x) = g(x)  ===>   x2 ( x + 1) =  2x( x + 1)   
 
===>  x(x+1) ( x - 2) = 0    ===>  x = 0 ;  x = -1  and  x = 2
 
f(0) = 0
f(-1) = -1 + 1  = 0
f(2) = 23 + 22 = 8 + 4 = 12
 
we have the intersection points ( 0 , 0 ) ;  (-1 , 0)  and (2, 12 ) 
 
when  -1 <  x < 0  we have  f(x) - g(x)  > 0   ----> f is over g
when  0 < x < 2    we have  f(x) - g(x)  < 0   ----> f is under g
 
thus :
 
 
 
 
 
 
hope this helps
You Don't Mess with the Panda
Tags: Math, Calculus
Oracle
Karma Points: 9,380
posted by Bpanda on 7/3/2008 2:21:19 AM  |  status: Live
Asker's Rating: Helpful   
T4RMINAT3R's comment:
"Thanks for the visual aid, along with great answer"
Response Details:
see the graph below:
 
 
hope this helps
You Don't Mess with the Panda
Tags: Math, Calculus
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