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posted by  short on 9/7/2008 3:03:57 AM  |  status: Live  

math

Course Textbook Chapter Problem
N/A N/A N/A 9 a
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posted by I, Mathemagician on 9/7/2008 3:11:52 AM  |  status: Live
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(15xy2-5x2y3+10x3y6)/(5x2y2)
It might be better to factor out like terms in the numerator.
5xy2(3-5xy+10x2y4)/5x2y2=(3-5xy+10x2y4)/x=(3/x)-5y+10xy4.

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Tags: Math, Precalculus
Pupil
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posted by Maedoc on 9/7/2008 3:20:10 AM  |  status: Live
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  From the numerator, you can pull out 5xy2, which will give you
The 5, an x, and the y's will cancel out, leaving you



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Tags: Math, Precalculus
Sage
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posted by Cowboy15 on 9/7/2008 3:39:46 AM  |  status: Live
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(15xy2-5x2y3+10x3y6)/(5x2y2)
 

 

(15xy^(2)-5x^(2)y^(3)+10x^(3)y^(6))/(5x^(2)y^(2))

 

(5xy^(2)(2x^(2)y^(4))+5xy^(2)(-xy)+5xy^(2)(3))/(5x^(2)y^(2))

 

(5xy^(2)(2x^(2)y^(4)-xy+3))/(5x^(2)y^(2))

 

(2x^(2)y^(4)-xy+3)/(x)

 

(2x^(2)y^(4))/(x)-(xy)/(x)+(3)/(x)

 

2xy^(4)-(xy)/(x)+(3)/(x)

 

ANSWER:   2xy^(4)-y+(3)/(x)



Tags: Math, Precalculus
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