Since P is on x axis then the y coordinate is 0 (Obvious right)
So we can say that coordinates of P is ( x , 0)
Now since the distance of P from the point ( -3 , 5 ) is 13 , ew can use the distance formula here,
Here d = 13 Given
(x1, y1) = (-3 , 5) given
(x2, y2) = ( x , 0)
now apply these values
Squaring both sides
Taking square root on both sides u get,
±12 = x +3
either x = 12 -3 or x = -12 -3
x = 9 x = -15
therefore two possible coordinates of P are (9,0) and (-15,0)
ANSWER
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