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Scholar
Karma Points: 386
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Date Posted: 7/24/2008 10:58:23 PM  Status: Live
lifesaver. Algebra probability problem,
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Hi, I have trouble on solving this problem.  I cannot figure out how to get to the answer.  Showing work is appreciated =).  Thank you so much.
 
A routlette wheel consists of 38 slots.  Thirty-six of these are numbered 1-36 and colored red or black so that there are 9 red even-numbered slots, 9 black odd-numbered slots, etc.  These slots occur with equal probability.  The 2 slots marked 0 or 00 are each 3 times as likely to occur as any one of the other 36.  What is the probability that a red even number, a red 23, or a 00 will occur on one roll of the wheel?
 
The answer to this problem is 13/42
 
~ Please rate and I hope it helps! ~ 
 

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Apprentice
Karma Points: 135
Date Posted: 7/24/2008 11:23:44 PM  Status: Live
Asker's Rating: Lifesaver   
Response:
ok so you know that you will be adding the probabilities of the 3 separate events (red even, red 23, 00).

If I were to give each number a weight (how likely it is to be landed on), i would give each number from 1-36 a "one" and 0 and 00 a "three" each. When you add these weights, you get 36+3+3=42.

the prob of getting an even red is the number of even reds there are, which is 9.
the prob of getting a red 23 is the # of red 23's there are on the board, which is 1.
the prob of getting a 00 is the number of 00's there are on the board, which is 1, multiplied by the weight or likelihood of landing on the 00, which is 3. so the prob of getting 00 is 3/42

so now we add 9/42 + 1/42 + 3/42 = 13/42
:)
Babie Doll's Comment:
:) wow thanks a lot for making me understand it! if u ever have anything that u need help, i'll be sure to try and help out, just inbox me! thanks a lot! :)




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