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posted by  FDRHS on 7/1/2008 9:58:20 AM  |  status: Live  

Find A Math Expression

Course Textbook Chapter Problem
Precalculus Precalculus (7th) by Sullivan 1 66
Question Details:
A hot-air balloon, headed due east at an average speed of 15 miles per hour and at a constant altitude of 100 feet, passes over an intersection.  Find an expression for the distance d (measured in feet) from the balloon to the intersection t seconds later.
 
 
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Sage
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posted by Betel on 7/1/2008 10:10:02 AM  |  status: Live
Asker's Rating: Lifesaver   
FDRHS's comment:
"Betel is the greatest!"
Response Details:

First, convert mph to feet per second:

15miles/hour * 5280feet/mile * 1hour/3600 seconds = 22 ft/s

    


Now, by Pythagorean Theorem:

d = √{(100ft)2 + [(22ft/s)(t)]2}

Or in a simpler form, noting the answer will come out in feet:





Hope that helps!

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Tags: Math, Precalculus
Oracle
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posted by Ratso Rizzo on 7/1/2008 10:12:57 AM  |  status: Live
Asker's Rating: Helpful   
FDRHS's comment:
"A job well-done!"
Response Details:
First, 15 miles per hour converts to 22 feet per second
 

 
 
By the pythagorean theorem,
d2=1002+(22t)2
d = √(100000+484t2)
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Tags: Math, Precalculus
Sage
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(Maple Leaf International School)
posted by Steve_R on 7/1/2008 10:19:29 AM  |  status: Live
Asker's Rating: Helpful   
FDRHS's comment:
"Your picture is somewhat clear but not as clear as the other two replies. Thanks anyway."
Response Details:
As a point of reference, assume that at t = 0 hours, the balloon is directly over the intersection.
 
At some time t1, the balloon is at position x1 relative to intersection
 
At some time t2, the balloon is at position x2 relative to intersection
 
At any time 't', the balloon is at position 'x' relative to intersection
 
 
 
Relative to the air, the balloon covers dair = *15 mph * 5280 miles / feet) * 1 hour / 3600 s) * t     
 
                                                               = 22 t     where 'd' is in feet  and t in seconds
 
Relative to ground,  dground = x = √(1002 + (22 t)2
 
                                                  = √(10000 + 484 t2)
 
 
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Tags: Math, Precalculus
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