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Trigonometry

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Scholar
Karma Points: 204
Respect (90%):
Date Posted: 6/30/2008 11:58:31 AM  Status: Closed
Trigonometry
Course Textbook Chapter Problem
N/A N/A N/A N/A
Question Details:
A bullet is fired into the air with an initial velocity of 1800 ft per second, at an angle of 60 degrees from the horizontal. Find the magnitudes of the horizontal and vertical vector components of the velocity vector.
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Answers:

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Oracle
Karma Points: 15,002
Date Posted: 6/30/2008 12:37:03 PM  Status: Live
Asker's Rating: Helpful   
Response:


Remember that cosθ = adjacent / hypotenuse
                        sinθ = opposite /hypotenuse
So we can rewrite these two equations as:

horizontal component=adjacent = hypotenuse*cosθ

vertical component = opposite = hypotenuse *sinθ

Again to find the horizontal and vertical vector components, we can apply the formula:

Horizontal component = V*cosθ
                                  = 1800 *cos60
                                  = 900 ft per second
Vertical component = V*sinθ
                               = 1800*sin60
                               = 1559 ft per second
brop's Comment:
thank you
Hope this helps!  Please take the time to rate my answer accordingly.  Thanks! 

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Scholar
Karma Points: 210
Date Posted: 6/30/2008 12:41:58 PM  Status: Live
Asker's Rating: Lifesaver   
Response:
 
so you assume a right triangle, and apply what you know about sines and cosines.
 
sin(angle)= opposite/hypotanuse
sin(60)= y/1800
y=1800*sin(60)=1558.846
 
cos(angle)=opposite/ adjacent
cos(60)= x/1800
x=1800*cos(60)= 900
 
 
brop's Comment:
thank you very much



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