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Date Posted: 7/25/2008 3:21:46 AM  Status: Live
mth603
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Date Posted: 7/25/2008 7:49:58 AM  Status: Live
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Response:
(1)Trapezoidal rule :
where h = .
here, n = 8, since we are dividing the interval into 8 equal parts.
So, a = x0 = 0, x1 = 1/8=0.125,x2 = 0.25, x3 = 0.375, x4= 0.5, x5= 0.625, x6= 0.75, x7= 0.875, x8= b = 1.
 
      xi         f(xi)=e2xi
   
 
(2) Simpson's rule :   Let 2m = 8. h= =.
              = [1 + 4(e1/4+e3/4+e5/4+e7/4)+ 2(e1/2  + e + e3/2) + e2 ].
              =  [1 +4(1.284 + 2.117 + 3.4903 +5.7546) + 2(1.6487 + 2.7182 + 4.4816) + 7.389 ]
              = [1 + 50.5836 + 17.697 + 7.389 ]
              = 3.1529.
 
It's actual value is :
 
(1) prcentage error from it's true value in trapezoidal case :
     Trapezoidal value - actual value = 3.2111 - 2.6945 = .5166.
     Percentage error from it's true value = * 100 %= 16.08%.
∴ 16% error from it's true value.
 (2) Percentage error from it's true value in simpson's rule :
    Simpson's value - actual value = 3.1529 - 2.6945 = 0.4584.
     Percentage error from it's actual value = *100% = 17.01%
∴ 17.01 %  error from it's true value. 



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